请问ln0.01/ln0.2怎么算?

日期:7个月前

n >=  ln0.01/ln0.2

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  • n >=  ln0.01/ln0.2 = lg0.01/lg0.2 = -2/( lg0.1 + lg2 ) = -2/( -1 + 0.301 ) = 2000/699;

    即 n ≥ 2.86123 。